A) 3i /( 5-2i) = (3i (5+2i))/((5-2i)(5+2i)) = (15i-6)/(5^2+2^2 ) = (15i-6)/29 =(15i-6)/29-6/29
B) (1-3i)^3=(1-3i)(1-3i)=1-3i-3i-9=(-8-6i)(1-3i)=-8+24i-6i-18i=-26+18
C) (5-2i)—7+4i=12-6i
D) 5-(7-8i)= -2+8i
E) 7(2-3i)=14-21i
F) i/(7+i)= (i(7-i))/((7+1)(7-i))= (7i+1)/(7^2+1^2 )= (7i+1)/50= 1/50+7i/5o
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